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TonyKim9401
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Dec 20, 2024
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| if not preorder or not inorder: | ||
| return None | ||
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| root = TreeNode(preorder[0]) | ||
| mid = inorder.index(preorder[0]) | ||
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| root.left = self.buildTree(preorder[1:mid+1], inorder[:mid]) | ||
| root.right = self.buildTree(preorder[mid+1:], inorder[mid+1:]) |
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파이썬과 재귀함수가 조합이 잘 된것 같습니다!
TonyKim9401
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Dec 20, 2024
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TonyKim9401
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2주차 문제풀이도 고생 많으셨습니다!
파이썬 활용이 너무 잘 된것 같습니다.
3주차도 파이팅입니다!
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